Java ResultSet isAfterLast() method with example

... isAfterLast; isBeforeFirst; isClosed; isFirst; isLast; isNull; move; moveToFirst ... cursor position is out of bounds. Subclass implementations of the get ...

How to use. isAfterLast. method. in. android.database.Cursor · Best Java code snippets using android.database.Cursor.isAfterLast (Showing top 20 results out of ...

2016年5月2日 — Cursor isAfterLast() returns true when reaching last row ... Essentially in the first method, the while loop runs 1 time less than the second one.

... isAfterLast(). Returns whether the cursor is pointing to the position after the last row. abstract boolean, isBeforeFirst(). Returns whether the cursor is ...

Returns whether the cursor is pointing to the position after the last row. Usage. From source file:org.artifactly.client.service.LocalServiceImpl.java private ...

2022年11月18日 — Retrieves whether the cursor is after the last row in this SQLServerResultSet object. Syntax. Copy.

2023年6月1日 — 如果搭配動態資料指標使用這個方法，包括順向的唯讀資料指標，而且selectMethod 連接屬性設定為cursor，則會發生例外狀況。 另請參閱.

2019年7月30日 — The isAfterLast() method of the ResultSet interface is used to determine whether the cursor is after the end of the ResultSet. rs.isAfterLast();.

2015年8月7日 — cursor.isAfterLast() returns true when cursor is at last row position. Adding a ! (not) means perform till it is not at the end of cursor.

2020年8月20日 — 文章浏览阅读902次。I frequently see code which involves iterating over the result of a database query, doing something_cursor.isafterlast()